Integrand size = 19, antiderivative size = 291 \[ \int \frac {\left (b x^{2/3}+a x\right )^{3/2}}{x^5} \, dx=-\frac {a \sqrt {b x^{2/3}+a x}}{16 x^3}-\frac {a^2 \sqrt {b x^{2/3}+a x}}{224 b x^{8/3}}+\frac {13 a^3 \sqrt {b x^{2/3}+a x}}{2688 b^2 x^{7/3}}-\frac {143 a^4 \sqrt {b x^{2/3}+a x}}{26880 b^3 x^2}+\frac {429 a^5 \sqrt {b x^{2/3}+a x}}{71680 b^4 x^{5/3}}-\frac {143 a^6 \sqrt {b x^{2/3}+a x}}{20480 b^5 x^{4/3}}+\frac {143 a^7 \sqrt {b x^{2/3}+a x}}{16384 b^6 x}-\frac {429 a^8 \sqrt {b x^{2/3}+a x}}{32768 b^7 x^{2/3}}-\frac {\left (b x^{2/3}+a x\right )^{3/2}}{3 x^4}+\frac {429 a^9 \text {arctanh}\left (\frac {\sqrt {b} \sqrt [3]{x}}{\sqrt {b x^{2/3}+a x}}\right )}{32768 b^{15/2}} \]
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Time = 0.33 (sec) , antiderivative size = 291, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.211, Rules used = {2045, 2050, 2054, 212} \[ \int \frac {\left (b x^{2/3}+a x\right )^{3/2}}{x^5} \, dx=\frac {429 a^9 \text {arctanh}\left (\frac {\sqrt {b} \sqrt [3]{x}}{\sqrt {a x+b x^{2/3}}}\right )}{32768 b^{15/2}}-\frac {429 a^8 \sqrt {a x+b x^{2/3}}}{32768 b^7 x^{2/3}}+\frac {143 a^7 \sqrt {a x+b x^{2/3}}}{16384 b^6 x}-\frac {143 a^6 \sqrt {a x+b x^{2/3}}}{20480 b^5 x^{4/3}}+\frac {429 a^5 \sqrt {a x+b x^{2/3}}}{71680 b^4 x^{5/3}}-\frac {143 a^4 \sqrt {a x+b x^{2/3}}}{26880 b^3 x^2}+\frac {13 a^3 \sqrt {a x+b x^{2/3}}}{2688 b^2 x^{7/3}}-\frac {a^2 \sqrt {a x+b x^{2/3}}}{224 b x^{8/3}}-\frac {\left (a x+b x^{2/3}\right )^{3/2}}{3 x^4}-\frac {a \sqrt {a x+b x^{2/3}}}{16 x^3} \]
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Rule 212
Rule 2045
Rule 2050
Rule 2054
Rubi steps \begin{align*} \text {integral}& = -\frac {\left (b x^{2/3}+a x\right )^{3/2}}{3 x^4}+\frac {1}{6} a \int \frac {\sqrt {b x^{2/3}+a x}}{x^4} \, dx \\ & = -\frac {a \sqrt {b x^{2/3}+a x}}{16 x^3}-\frac {\left (b x^{2/3}+a x\right )^{3/2}}{3 x^4}+\frac {1}{96} a^2 \int \frac {1}{x^3 \sqrt {b x^{2/3}+a x}} \, dx \\ & = -\frac {a \sqrt {b x^{2/3}+a x}}{16 x^3}-\frac {a^2 \sqrt {b x^{2/3}+a x}}{224 b x^{8/3}}-\frac {\left (b x^{2/3}+a x\right )^{3/2}}{3 x^4}-\frac {\left (13 a^3\right ) \int \frac {1}{x^{8/3} \sqrt {b x^{2/3}+a x}} \, dx}{1344 b} \\ & = -\frac {a \sqrt {b x^{2/3}+a x}}{16 x^3}-\frac {a^2 \sqrt {b x^{2/3}+a x}}{224 b x^{8/3}}+\frac {13 a^3 \sqrt {b x^{2/3}+a x}}{2688 b^2 x^{7/3}}-\frac {\left (b x^{2/3}+a x\right )^{3/2}}{3 x^4}+\frac {\left (143 a^4\right ) \int \frac {1}{x^{7/3} \sqrt {b x^{2/3}+a x}} \, dx}{16128 b^2} \\ & = -\frac {a \sqrt {b x^{2/3}+a x}}{16 x^3}-\frac {a^2 \sqrt {b x^{2/3}+a x}}{224 b x^{8/3}}+\frac {13 a^3 \sqrt {b x^{2/3}+a x}}{2688 b^2 x^{7/3}}-\frac {143 a^4 \sqrt {b x^{2/3}+a x}}{26880 b^3 x^2}-\frac {\left (b x^{2/3}+a x\right )^{3/2}}{3 x^4}-\frac {\left (143 a^5\right ) \int \frac {1}{x^2 \sqrt {b x^{2/3}+a x}} \, dx}{17920 b^3} \\ & = -\frac {a \sqrt {b x^{2/3}+a x}}{16 x^3}-\frac {a^2 \sqrt {b x^{2/3}+a x}}{224 b x^{8/3}}+\frac {13 a^3 \sqrt {b x^{2/3}+a x}}{2688 b^2 x^{7/3}}-\frac {143 a^4 \sqrt {b x^{2/3}+a x}}{26880 b^3 x^2}+\frac {429 a^5 \sqrt {b x^{2/3}+a x}}{71680 b^4 x^{5/3}}-\frac {\left (b x^{2/3}+a x\right )^{3/2}}{3 x^4}+\frac {\left (143 a^6\right ) \int \frac {1}{x^{5/3} \sqrt {b x^{2/3}+a x}} \, dx}{20480 b^4} \\ & = -\frac {a \sqrt {b x^{2/3}+a x}}{16 x^3}-\frac {a^2 \sqrt {b x^{2/3}+a x}}{224 b x^{8/3}}+\frac {13 a^3 \sqrt {b x^{2/3}+a x}}{2688 b^2 x^{7/3}}-\frac {143 a^4 \sqrt {b x^{2/3}+a x}}{26880 b^3 x^2}+\frac {429 a^5 \sqrt {b x^{2/3}+a x}}{71680 b^4 x^{5/3}}-\frac {143 a^6 \sqrt {b x^{2/3}+a x}}{20480 b^5 x^{4/3}}-\frac {\left (b x^{2/3}+a x\right )^{3/2}}{3 x^4}-\frac {\left (143 a^7\right ) \int \frac {1}{x^{4/3} \sqrt {b x^{2/3}+a x}} \, dx}{24576 b^5} \\ & = -\frac {a \sqrt {b x^{2/3}+a x}}{16 x^3}-\frac {a^2 \sqrt {b x^{2/3}+a x}}{224 b x^{8/3}}+\frac {13 a^3 \sqrt {b x^{2/3}+a x}}{2688 b^2 x^{7/3}}-\frac {143 a^4 \sqrt {b x^{2/3}+a x}}{26880 b^3 x^2}+\frac {429 a^5 \sqrt {b x^{2/3}+a x}}{71680 b^4 x^{5/3}}-\frac {143 a^6 \sqrt {b x^{2/3}+a x}}{20480 b^5 x^{4/3}}+\frac {143 a^7 \sqrt {b x^{2/3}+a x}}{16384 b^6 x}-\frac {\left (b x^{2/3}+a x\right )^{3/2}}{3 x^4}+\frac {\left (143 a^8\right ) \int \frac {1}{x \sqrt {b x^{2/3}+a x}} \, dx}{32768 b^6} \\ & = -\frac {a \sqrt {b x^{2/3}+a x}}{16 x^3}-\frac {a^2 \sqrt {b x^{2/3}+a x}}{224 b x^{8/3}}+\frac {13 a^3 \sqrt {b x^{2/3}+a x}}{2688 b^2 x^{7/3}}-\frac {143 a^4 \sqrt {b x^{2/3}+a x}}{26880 b^3 x^2}+\frac {429 a^5 \sqrt {b x^{2/3}+a x}}{71680 b^4 x^{5/3}}-\frac {143 a^6 \sqrt {b x^{2/3}+a x}}{20480 b^5 x^{4/3}}+\frac {143 a^7 \sqrt {b x^{2/3}+a x}}{16384 b^6 x}-\frac {429 a^8 \sqrt {b x^{2/3}+a x}}{32768 b^7 x^{2/3}}-\frac {\left (b x^{2/3}+a x\right )^{3/2}}{3 x^4}-\frac {\left (143 a^9\right ) \int \frac {1}{x^{2/3} \sqrt {b x^{2/3}+a x}} \, dx}{65536 b^7} \\ & = -\frac {a \sqrt {b x^{2/3}+a x}}{16 x^3}-\frac {a^2 \sqrt {b x^{2/3}+a x}}{224 b x^{8/3}}+\frac {13 a^3 \sqrt {b x^{2/3}+a x}}{2688 b^2 x^{7/3}}-\frac {143 a^4 \sqrt {b x^{2/3}+a x}}{26880 b^3 x^2}+\frac {429 a^5 \sqrt {b x^{2/3}+a x}}{71680 b^4 x^{5/3}}-\frac {143 a^6 \sqrt {b x^{2/3}+a x}}{20480 b^5 x^{4/3}}+\frac {143 a^7 \sqrt {b x^{2/3}+a x}}{16384 b^6 x}-\frac {429 a^8 \sqrt {b x^{2/3}+a x}}{32768 b^7 x^{2/3}}-\frac {\left (b x^{2/3}+a x\right )^{3/2}}{3 x^4}+\frac {\left (429 a^9\right ) \text {Subst}\left (\int \frac {1}{1-b x^2} \, dx,x,\frac {\sqrt [3]{x}}{\sqrt {b x^{2/3}+a x}}\right )}{32768 b^7} \\ & = -\frac {a \sqrt {b x^{2/3}+a x}}{16 x^3}-\frac {a^2 \sqrt {b x^{2/3}+a x}}{224 b x^{8/3}}+\frac {13 a^3 \sqrt {b x^{2/3}+a x}}{2688 b^2 x^{7/3}}-\frac {143 a^4 \sqrt {b x^{2/3}+a x}}{26880 b^3 x^2}+\frac {429 a^5 \sqrt {b x^{2/3}+a x}}{71680 b^4 x^{5/3}}-\frac {143 a^6 \sqrt {b x^{2/3}+a x}}{20480 b^5 x^{4/3}}+\frac {143 a^7 \sqrt {b x^{2/3}+a x}}{16384 b^6 x}-\frac {429 a^8 \sqrt {b x^{2/3}+a x}}{32768 b^7 x^{2/3}}-\frac {\left (b x^{2/3}+a x\right )^{3/2}}{3 x^4}+\frac {429 a^9 \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt [3]{x}}{\sqrt {b x^{2/3}+a x}}\right )}{32768 b^{15/2}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 10.07 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.21 \[ \int \frac {\left (b x^{2/3}+a x\right )^{3/2}}{x^5} \, dx=\frac {6 a^9 \left (b+a \sqrt [3]{x}\right )^2 \sqrt {b x^{2/3}+a x} \operatorname {Hypergeometric2F1}\left (\frac {5}{2},10,\frac {7}{2},1+\frac {a \sqrt [3]{x}}{b}\right )}{5 b^{10} \sqrt [3]{x}} \]
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Time = 1.85 (sec) , antiderivative size = 181, normalized size of antiderivative = 0.62
method | result | size |
derivativedivides | \(\frac {\left (b \,x^{\frac {2}{3}}+a x \right )^{\frac {3}{2}} \left (45045 b^{\frac {31}{2}} \sqrt {b +a \,x^{\frac {1}{3}}}-390390 b^{\frac {29}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {3}{2}}-2633274 b^{\frac {27}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {5}{2}}+4349826 b^{\frac {25}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {7}{2}}-4685824 b^{\frac {23}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {9}{2}}+3317886 b^{\frac {21}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {11}{2}}-1495494 b^{\frac {19}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {13}{2}}+390390 b^{\frac {17}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {15}{2}}-45045 b^{\frac {15}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {17}{2}}+45045 \,\operatorname {arctanh}\left (\frac {\sqrt {b +a \,x^{\frac {1}{3}}}}{\sqrt {b}}\right ) b^{7} a^{9} x^{3}\right )}{3440640 x^{4} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {3}{2}} b^{\frac {29}{2}}}\) | \(181\) |
default | \(\frac {\left (b \,x^{\frac {2}{3}}+a x \right )^{\frac {3}{2}} \left (45045 b^{\frac {31}{2}} \sqrt {b +a \,x^{\frac {1}{3}}}-390390 b^{\frac {29}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {3}{2}}-2633274 b^{\frac {27}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {5}{2}}+4349826 b^{\frac {25}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {7}{2}}-4685824 b^{\frac {23}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {9}{2}}+3317886 b^{\frac {21}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {11}{2}}-1495494 b^{\frac {19}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {13}{2}}+390390 b^{\frac {17}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {15}{2}}-45045 b^{\frac {15}{2}} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {17}{2}}+45045 \,\operatorname {arctanh}\left (\frac {\sqrt {b +a \,x^{\frac {1}{3}}}}{\sqrt {b}}\right ) b^{7} a^{9} x^{3}\right )}{3440640 x^{4} \left (b +a \,x^{\frac {1}{3}}\right )^{\frac {3}{2}} b^{\frac {29}{2}}}\) | \(181\) |
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Timed out. \[ \int \frac {\left (b x^{2/3}+a x\right )^{3/2}}{x^5} \, dx=\text {Timed out} \]
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\[ \int \frac {\left (b x^{2/3}+a x\right )^{3/2}}{x^5} \, dx=\int \frac {\left (a x + b x^{\frac {2}{3}}\right )^{\frac {3}{2}}}{x^{5}}\, dx \]
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\[ \int \frac {\left (b x^{2/3}+a x\right )^{3/2}}{x^5} \, dx=\int { \frac {{\left (a x + b x^{\frac {2}{3}}\right )}^{\frac {3}{2}}}{x^{5}} \,d x } \]
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Time = 0.54 (sec) , antiderivative size = 194, normalized size of antiderivative = 0.67 \[ \int \frac {\left (b x^{2/3}+a x\right )^{3/2}}{x^5} \, dx=-\frac {\frac {45045 \, a^{10} \arctan \left (\frac {\sqrt {a x^{\frac {1}{3}} + b}}{\sqrt {-b}}\right )}{\sqrt {-b} b^{7}} + \frac {45045 \, {\left (a x^{\frac {1}{3}} + b\right )}^{\frac {17}{2}} a^{10} - 390390 \, {\left (a x^{\frac {1}{3}} + b\right )}^{\frac {15}{2}} a^{10} b + 1495494 \, {\left (a x^{\frac {1}{3}} + b\right )}^{\frac {13}{2}} a^{10} b^{2} - 3317886 \, {\left (a x^{\frac {1}{3}} + b\right )}^{\frac {11}{2}} a^{10} b^{3} + 4685824 \, {\left (a x^{\frac {1}{3}} + b\right )}^{\frac {9}{2}} a^{10} b^{4} - 4349826 \, {\left (a x^{\frac {1}{3}} + b\right )}^{\frac {7}{2}} a^{10} b^{5} + 2633274 \, {\left (a x^{\frac {1}{3}} + b\right )}^{\frac {5}{2}} a^{10} b^{6} + 390390 \, {\left (a x^{\frac {1}{3}} + b\right )}^{\frac {3}{2}} a^{10} b^{7} - 45045 \, \sqrt {a x^{\frac {1}{3}} + b} a^{10} b^{8}}{a^{9} b^{7} x^{3}}}{3440640 \, a} \]
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Timed out. \[ \int \frac {\left (b x^{2/3}+a x\right )^{3/2}}{x^5} \, dx=\int \frac {{\left (a\,x+b\,x^{2/3}\right )}^{3/2}}{x^5} \,d x \]
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